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Find the co-ordinates of A(x,0) & B(0,y) where C(3,5) is the mid point of \(\overline {AB} \)
A(6,0) & B(0,10)
Find the equation of \(\overline {AP} \), where P is the midpoint of \(\overline {BC} \) & vertices are A(5,7), B(-3,7) & C(7,9)
Equation of AP is
(two-point from)
If the line\(\dfrac{x}{a} + \dfrac{y}{b} = 1\) passes through the points (3,4) and (-4,7), then (a,b) is
Given,
Since, the points (3,4) and (-4,7) lies on this line.
Find the co-ordinate of incenter of the triangle with vertices (0,0), (3,4) & (4,0) is
Let A(0,0), B(3,4) and C(4,0).
The line \(\dfrac{x}{a} + \dfrac{y}{b} = 1\) moves in such a way that \(\dfrac{1}{{{a^2}}} + \dfrac{1}{{{b^2}}} = \dfrac{1}{{{c^2}}}\), where c is a constant. The locus of the foot of the perendicular from origin on the line is
Given, …(i)
Equation of line passes through origin & perpendicular
to line(i) is
Find the value of \(\lambda \), if the line \(\left( {2x + 3y + 4} \right) + \lambda \left( {6x – y + 12} \right) = 0\) are passes through (1,2) is
Given,
The line passes through (1,2)
then,